适配英文排版

pull/5/head
fengyuecanzhu 3 years ago
parent 29cdeec30a
commit 8a777a1f7a
  1. 182
      app/src/main/java/xyz/fycz/myreader/ai/BookWordCountPre.java
  2. 295
      app/src/main/java/xyz/fycz/myreader/ai/MatrixUtil.java
  3. 5
      app/src/main/java/xyz/fycz/myreader/util/utils/AdUtils.java

@ -1,182 +0,0 @@
package xyz.fycz.myreader.ai;
import android.util.Log;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Random;
import xyz.fycz.myreader.greendao.entity.Book;
import xyz.fycz.myreader.greendao.entity.Chapter;
import xyz.fycz.myreader.greendao.service.ChapterService;
/**
* 预测书籍字数
*
* @author fengyue
* @date 2021/4/18 16:54
*/
public class BookWordCountPre {
private static final String TAG = BookWordCountPre.class.getSimpleName();
private double lr = 0.001;
private Book book;
private List<Chapter> chapters;
private double[][] trainData;
private double[][] target;
private double[][] weights1;
//private double[][] weights2;
private double[][] testData;
private double median;
private static Random rand = new Random();
public BookWordCountPre(Book book) {
this.book = book;
this.chapters = ChapterService.getInstance().findBookAllChapterByBookId(book.getId());
}
//进行训练
public boolean train() {
if (!preData()) {
Log.i(TAG, String.format("《%s》缓存章节数量过少,无法进行训练", book.getName()));
return false;
}
Log.i(TAG, String.format("《%s》开始进行训练", book.getName()));
double loss = 0;
double eps = 0.0000000001;
double[][] gradient1;
//double[][] gradient2;
double[][] adagrad1 = new double[trainData[0].length][1];
//double[][] adagrad2 = new double[trainData[0].length][1];
//double[][] dl_dw = new double[trainData[0].length][1];
int maxEpoch;
maxEpoch = 1000 / trainData.length;
if (maxEpoch < 10) maxEpoch = 10;
for (int epoch = 0; epoch < maxEpoch; epoch++) {
shuffle(trainData, target);
for (int j = 0; j < trainData.length; j++) {
double[][] oneData = MatrixUtil.to2dMatrix(trainData[j], false);
double[][] oneTarget = MatrixUtil.to2dMatrix(target[j], true);
double[][] out = getOut(oneData);
loss = Math.sqrt(MatrixUtil.sum(MatrixUtil.pow(MatrixUtil.sub(out, oneTarget), 2)) / 2);
/*dl_dw = MatrixUtil.sub(
MatrixUtil.add(
MatrixUtil.dot(MatrixUtil.pow(oneData, 2), weights2),
MatrixUtil.dot(oneData, weights2)),
oneTarget
);*/
gradient1 = MatrixUtil.dot(MatrixUtil.transpose(oneData), MatrixUtil.sub(out, oneTarget));
//gradient1 = MatrixUtil.dot(MatrixUtil.transpose(MatrixUtil.pow(oneData, 2)), dl_dw);
//gradient2 = MatrixUtil.dot(MatrixUtil.transpose(oneData), dl_dw);
adagrad1 = MatrixUtil.add(adagrad1, MatrixUtil.pow(gradient1, 2));
//adagrad2 = MatrixUtil.add(adagrad1, MatrixUtil.pow(gradient2, 2));
weights1 = MatrixUtil.sub(weights1, MatrixUtil.divide(MatrixUtil.dot(gradient1, lr),
MatrixUtil.sqrt(MatrixUtil.add(adagrad1, eps))));
/*weights2 = MatrixUtil.sub(weights2, MatrixUtil.divide(MatrixUtil.dot(gradient2, lr),
MatrixUtil.sqrt(MatrixUtil.add(adagrad2, eps))));*/
}
Log.i(TAG, String.format("《%s》-> epoch=%d,loss=%f", book.getName(), epoch, loss));
}
return true;
}
//进行预测并获得书籍总字数
public int predict() {
double[][] pre = getOut(testData);
double[] preVec = MatrixUtil.toVector(pre);
Arrays.sort(preVec);
int k = (int) (preVec[preVec.length / 2 + 1] / median);
//int k = (int) ((MatrixUtil.sum(pre) / pre.length) / median);
pre = MatrixUtil.divide(pre, k);
/*for (int i = 0; i < pre.length; i++) {
pre[i][0] = median;
}*/
Log.i(TAG, String.format("k=%d->《%s》的预测数据%s", k, book.getName(),
Arrays.toString(MatrixUtil.toVector(pre))));
return (int) (MatrixUtil.sum(pre) + MatrixUtil.sum(target));
}
private double[][] getOut(double[][] data) {
/*return MatrixUtil.add(MatrixUtil.dot(MatrixUtil.pow(data, 2), weights2),
MatrixUtil.dot(data, weights1));*/
return MatrixUtil.dot(data, weights1);
}
//准备训练数据
private boolean preData() {
rand.setSeed(10);
List<Chapter> catheChapters = new ArrayList<>();
List<Chapter> unCatheChapters = new ArrayList<>();
//章节最长标题长度
int maxTitleLen = 0;
//获取已缓存章节
for (Chapter chapter : chapters) {
if (ChapterService.isChapterCached(book.getId(), chapter.getTitle())) {
catheChapters.add(chapter);
} else {
unCatheChapters.add(chapter);
}
if (maxTitleLen < chapter.getTitle().length()) {
maxTitleLen = chapter.getTitle().length();
}
}
Log.i(TAG, String.format("《%s》已缓存章节数量:%d,最大章节标题长度:%d",
book.getName(), catheChapters.size(), maxTitleLen));
if (catheChapters.size() <= 10) return false;
//创建训练数据
trainData = new double[catheChapters.size()][maxTitleLen + 1];
//创建测试数据
testData = new double[chapters.size() - catheChapters.size()][maxTitleLen + 1];
//创建权重矩阵
weights1 = new double[maxTitleLen + 1][1];
//weights2 = new double[maxTitleLen + 1][1];
//创建目标矩阵
target = new double[catheChapters.size()][1];
for (int i = 0; i < catheChapters.size(); i++) {
Chapter chapter = catheChapters.get(i);
char[] charArr = chapter.getTitle().replaceAll("[((【{]", "").toCharArray();
for (int j = 0; j < charArr.length; j++) {
trainData[i][j] = charArr[j];
}
trainData[i][maxTitleLen] = 1;
target[i][0] = ChapterService.countChar(book.getId(), chapter.getTitle());
}
for (int i = 0; i < maxTitleLen + 1; i++) {
weights1[i][0] = rand.nextDouble();
//weights2[i][0] = Math.random();
}
for (int i = 0; i < unCatheChapters.size(); i++) {
Chapter chapter = unCatheChapters.get(i);
char[] charArr = chapter.getTitle().toCharArray();
for (int j = 0; j < charArr.length; j++) {
testData[i][j] = charArr[j];
}
testData[i][maxTitleLen] = 1;
}
/*double[] tem = MatrixUtil.toVector(target);
Arrays.sort(tem);
median = tem[tem.length / 2 + 1];*/
median = MatrixUtil.sum(target) / target.length;
return true;
}
public static <T> void swap(T[] a, int i, int j) {
T temp = a[i];
a[i] = a[j];
a[j] = temp;
}
public static <T> void shuffle(T[]... arr) {
int length = arr[0].length;
for (int i = length; i > 0; i--) {
int randInd = rand.nextInt(i);
for (T[] ts : arr) {
swap(ts, randInd, i - 1);
}
}
}
}

@ -1,295 +0,0 @@
package xyz.fycz.myreader.ai;
/**
* @author fengyue
* @date 2021/4/7 16:10
*/
public class MatrixUtil {
//矩阵加法 C=A+B
public static double[][] add(double[][] m1, double[][] m2) {
if (m1 == null || m2 == null ||
m1.length != m2.length ||
m1[0].length != m2[0].length) {
return null;
}
double[][] m = new double[m1.length][m1[0].length];
for (int i = 0; i < m.length; ++i) {
for (int j = 0; j < m[i].length; ++j) {
m[i][j] = m1[i][j] + m2[i][j];
}
}
return m;
}
public static double[][] add(double[][] m, double a) {
if (m == null) {
return null;
}
double[][] retM = new double[m.length][m[0].length];
for (int i = 0; i < retM.length; ++i) {
for (int j = 0; j < retM[i].length; ++j) {
retM[i][j] = m[i][j] + a;
}
}
return retM;
}
public static double[][] sub(double[][] m1, double[][] m2) {
if (m1 == null || m2 == null ||
m1.length != m2.length ||
m1[0].length != m2[0].length) {
return null;
}
double[][] m = new double[m1.length][m1[0].length];
for (int i = 0; i < m.length; ++i) {
for (int j = 0; j < m[i].length; ++j) {
m[i][j] = m1[i][j] - m2[i][j];
}
}
return m;
}
//矩阵转置
public static double[][] transpose(double[][] m) {
if (m == null) return null;
double[][] mt = new double[m[0].length][m.length];
for (int i = 0; i < m.length; ++i) {
for (int j = 0; j < m[i].length; ++j) {
mt[j][i] = m[i][j];
}
}
return mt;
}
//矩阵相乘 C=A*B
public static double[][] dot(double[][] m1, double[][] m2) {
if (m1 == null || m2 == null || m1[0].length != m2.length)
return null;
double[][] m = new double[m1.length][m2[0].length];
for (int i = 0; i < m1.length; ++i) {
for (int j = 0; j < m2[0].length; ++j) {
for (int k = 0; k < m1[i].length; ++k) {
m[i][j] += m1[i][k] * m2[k][j];
}
}
}
return m;
}
//数乘矩阵
public static double[][] dot(double[][] m, double k) {
if (m == null) return null;
double[][] retM = new double[m.length][m[0].length];
for (int i = 0; i < m.length; i++) {
for (int j = 0; j < m[0].length; j++) {
retM[i][j] = m[i][j] * k;
}
}
return retM;
}
//同型矩阵除法
public static double[][] divide(double[][] m1, double[][] m2) {
if (m1 == null || m2 == null ||
m1.length != m2.length ||
m1[0].length != m2[0].length) {
return null;
}
double[][] retM = new double[m1.length][m1[0].length];
for (int i = 0; i < retM.length; ++i) {
for (int j = 0; j < retM[i].length; ++j) {
retM[i][j] = m1[i][j] / m2[i][j];
}
}
return retM;
}
//矩阵除数
public static double[][] divide(double[][] m, double k) {
if (m == null) return null;
double[][] retM = new double[m.length][m[0].length];
for (int i = 0; i < m.length; i++) {
for (int j = 0; j < m[0].length; j++) {
retM[i][j] = m[i][j] / k;
}
}
return retM;
}
//求矩阵行列式(需为方阵)
public static double det(double[][] m) {
if (m == null || m.length != m[0].length)
return 0;
if (m.length == 1)
return m[0][0];
else if (m.length == 2)
return det2(m);
else if (m.length == 3)
return det3(m);
else {
int re = 0;
for (int i = 0; i < m.length; ++i) {
re += (((i + 1) % 2) * 2 - 1) * det(companion(m, i, 0)) * m[i][0];
}
return re;
}
}
//求二阶行列式
public static double det2(double[][] m) {
if (m == null || m.length != 2 || m[0].length != 2)
return 0;
return m[0][0] * m[1][1] - m[1][0] * m[0][1];
}
//求三阶行列式
public static double det3(double[][] m) {
if (m == null || m.length != 3 || m[0].length != 3)
return 0;
double re = 0;
for (int i = 0; i < 3; ++i) {
int temp1 = 1;
for (int j = 0, k = i; j < 3; ++j, ++k) {
temp1 *= m[j][k % 3];
}
re += temp1;
temp1 = 1;
for (int j = 0, k = i; j < 3; ++j, --k) {
if (k < 0) k += 3;
temp1 *= m[j][k];
}
re -= temp1;
}
return re;
}
//求矩阵的逆(需方阵)
public static double[][] inv(double[][] m) {
if (m == null || m.length != m[0].length)
return null;
double A = det(m);
double[][] mi = new double[m.length][m[0].length];
for (int i = 0; i < m.length; ++i) {
for (int j = 0; j < m[i].length; ++j) {
double[][] temp = companion(m, i, j);
mi[j][i] = (((i + j + 1) % 2) * 2 - 1) * det(temp) / A;
}
}
return mi;
}
//求方阵代数余子式
public static double[][] companion(double[][] m, int x, int y) {
if (m == null || m.length <= x || m[0].length <= y ||
m.length == 1 || m[0].length == 1)
return null;
double[][] cm = new double[m.length - 1][m[0].length - 1];
int dx = 0;
for (int i = 0; i < m.length; ++i) {
if (i != x) {
int dy = 0;
for (int j = 0; j < m[i].length; ++j) {
if (j != y) {
cm[dx][dy++] = m[i][j];
}
}
++dx;
}
}
return cm;
}
//生成全为0的矩阵
public static double[][] zeros(int rows, int cols){
return new double[rows][cols];
}
//生成全为1的矩阵
public static double[][] ones(int rows, int cols){
return add(zeros(rows, cols), 1);
}
public static double sum(double[][] matrix){
double sum = 0;
for (double[] doubles : matrix) {
for (double aDouble : doubles) {
sum += aDouble;
}
}
return sum;
}
public static double[][] pow(double[][] matrix, int exponent){
if (matrix == null) return null;
double[][] retM = new double[matrix.length][matrix[0].length];
for (int i = 0; i < matrix.length; i++) {
for (int j = 0; j < matrix[i].length; j++) {
retM[i][j] = Math.pow(matrix[i][j], exponent);
}
}
return retM;
}
public static double[][] sqrt(double[][] matrix){
if (matrix == null) return null;
double[][] retM = new double[matrix.length][matrix[0].length];
for (int i = 0; i < matrix.length; i++) {
for (int j = 0; j < matrix[i].length; j++) {
retM[i][j] = Math.sqrt(matrix[i][j]);
}
}
return matrix;
}
public static double[][] to2dMatrix(double[] vector, boolean isCol){
if (vector == null) return null;
double[][] retM;
if (isCol) {
retM = new double[vector.length][1];
}else {
retM = new double[1][vector.length];
}
for (int i = 0; i < vector.length; i++) {
if (isCol) {
retM[i][0] = vector[i];
}else {
retM[0][i] = vector[i];
}
}
return retM;
}
public static double[] toVector(double[][] matrix){
double[] retV = null;
if (matrix.length == 1){
retV = new double[matrix[0].length];
double[] doubles = matrix[0];
System.arraycopy(doubles, 0, retV, 0, doubles.length);
}else if (matrix[0].length == 1){
retV = new double[matrix.length];
for (int i = 0; i < matrix.length; i++) {
retV[i] = matrix[i][0];
}
}
return retV;
}
}

@ -125,7 +125,10 @@ public class AdUtils {
public static void initAd() {
if (!hasInitAd) {
hasInitAd = true;
DdSdkHelper.init("", "", "",
"", "",
"", "",
App.getApplication(), true);
}
}
}

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