From d01d77fc4ffda227221a9a4919cb4bc196230d5d Mon Sep 17 00:00:00 2001
From: bushixuanqi <57338301+bushixuanqi@users.noreply.github.com>
Date: Sun, 4 Jul 2021 15:22:38 +0800
Subject: [PATCH] Update AnalyzeByJSoup.kt
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit

扩大索引向前的匹配范围，索引前无规则时相当于前面的规则是children
---
 .../java/io/legado/app/model/analyzeRule/AnalyzeByJSoup.kt    | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/app/src/main/java/io/legado/app/model/analyzeRule/AnalyzeByJSoup.kt b/app/src/main/java/io/legado/app/model/analyzeRule/AnalyzeByJSoup.kt
index be1615a46..3bb2e4e33 100644
--- a/app/src/main/java/io/legado/app/model/analyzeRule/AnalyzeByJSoup.kt
+++ b/app/src/main/java/io/legado/app/model/analyzeRule/AnalyzeByJSoup.kt
@@ -219,7 +219,7 @@ class AnalyzeByJSoup(doc: Any) {
 
             len-- //跳过尾部']'
 
-            while (len-- > 0) { //逆向遍历,至少有一位前置字符,如 [
+            while (len-- >= 0) { //逆向遍历,可以无前置规则
 
                 var rl = rus[len]
                 if (rl == ' ') continue //跳过空格
@@ -265,7 +265,7 @@ class AnalyzeByJSoup(doc: Any) {
                     curMinus = false //重置
                 }
             }
-        } else while (len --> 0) { //阅读原本写法，逆向遍历,至少两位前置字符,如 .
+        } else while (len-- >= 0) { //阅读原本写法，逆向遍历,可以无前置规则
 
             val rl = rus[len]
             if (rl == ' ') continue //跳过空格